Plz solve the above question
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Answered by
0
Answer:
45
Step-by-step explanation:
here you go-
⇒ In given figure KLMN is a parallelogram.
Let in figure PL⊥KO
So, ∠PLK=90
Let LM is angle bisector of ∠PLK such that,
∠MLP=∠KLM
Since, ∠PLK=90
∠MLP+∠KLM=90
2∠KLM=90
therefore, ∠KLM=45
Pls Mark me as Brainliest!!!
Answered by
4
i think answer of this question is (c) = 45°
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