Question

plz solve the answers​

Answer 1

Answer:

In triangle ABC

B+A+C=180°

60°+A+40°=180°

100°+A=180°

A=(180-100)°

A=80°

Now,AD bisects BC

therefore, BAD=CAD=1/2 of 80°

BAD=CAD=40°

Now,in triangle BAD,

BAD+ABD+ADB=180°

40°+60°+ADB=180°

100°+ADB=180°

ADB=80°

AL is perpendicular to BC

therefore,angle ALD=90°

Now,in triangle ALD

ALD+LAD+ADL=180°

90°+LAD+80°=180°

170°+LAD=180°

LAD=10°

COMPLETED....

Mark as brainliest........