Question

Plz solve the equation and verify your answer ​

Answer 1

Answer:

x = 1/3

Step-by-step explanation:

given

(6x - 2) / 9 + (3x + 5)/ 18 = 1/3

multiplying nr and dr by 2 on (6x - 2) / 9

we get

》(12x - 4) / 18 + (3x + 5)/ 18 = 1/3

》 ( 12x - 4 + 3x + 5 ) /18 = 1/3

》(15x + 1) / 18 = 1/3

》15x + 1 = 1/3 * 18

》15x + 1 = 6

》15x = 5

》x = 1/3

now substitute x in the equation to verify the answer

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Answer 2

Question:-

$\to \: \bf \: \frac{6x - 2}{9} + \frac{3x + 5}{18} = \frac{1}{3}$

Solution:-

$\to \: \bf \: \frac{6x - 2}{9} + \frac{3x + 5}{18} = \frac{1}{3}$

Take a lcm = 18

$\to \: \bf \: \frac{2(6x - 2)}{9 \times 2} + \frac{3x + 5}{18} = \frac{1}{3}$

$\to \: \bf \: \frac{12x - 4}{18} + \frac{3x + 5}{18} = \frac{1}{3}$

$\to \bf \: \frac{12x - 4 + 3x + 5}{18} = \frac{1}{3}$

$\to \bf \: \frac{15x + 1}{ \not18} = \frac{1}{ \not3}$

$\to \bf \: \frac{15x + 1}{ 6} = 1$

$\to \bf \: 15x + 1 = 6$

$\to \bf \: 15x = 5$

$\to \bf \: x = \frac{1}{3}$

To verify the answer put the value of x on given equation

$\to \: \bf \: \frac{6x - 2}{9} + \frac{3x + 5}{18} = \frac{1}{3}$

$\to \: \bf \: \frac{6 \times \frac{1}{3} - 2}{9} + \frac{3 \times \frac{1}{3} + 5}{18} = \frac{1}{3}$

$\to \: \bf \: \frac{2 - 2}{9} + \frac{1+ 5}{18} = \frac{1}{3}$

$\to \: \bf \: \frac{0}{9} + \frac{6}{18} = \frac{1}{3}$

$\to \: \bf \: 0 + \frac{1}{3} = \frac{1}{3}$

$\to \: \bf \: \frac{1}{3} = \frac{1}{3}$

LHS = RHS , Hence its verfiy