Plz solve the first one
Attachments:
Answers
Answered by
5
HOLA !!
----------------------
----------------------
∆ Refer the attachment
---------------------
---------------------
HOPE IT HELPS U☺☺☺
----------------------
----------------------
∆ Refer the attachment
---------------------
---------------------
HOPE IT HELPS U☺☺☺
Attachments:
shreya443:
thank u
Answered by
9
hey dear
here is your answer
==============================
Solution
==========
in first question
Given that
it is a right angle triangle
======================
side of right angle
AB = 24 cm
BC = 7 cm
hence as we know it is right angle
we use Pythagoras theorem
==========================
( H) ^2. = ( P) ^2 + ( B) ^2
(AC) ^2 = ( AB) ^2 + ( BC) ^2
( AC) ^2. = ( 24)^2 + ( 7)^2
( AC) ^2. = 576 + 49
( AC) ^2 = 625
AC = √625
AC = 25 cm
hence AC side 25 cm
=======================
then
To find sin A
Sin. A = 24 / 25
================
COS A = 7 /25
================
in second part
==============
to find Sin C
we use formula
= perpendicular / hypotenuse
============================
Sin C = 24 /25
===============
COS C. = Base / hypotenuse
============================
COS C = 7 /25
===================
hope it helps
thank you
here is your answer
==============================
Solution
==========
in first question
Given that
it is a right angle triangle
======================
side of right angle
AB = 24 cm
BC = 7 cm
hence as we know it is right angle
we use Pythagoras theorem
==========================
( H) ^2. = ( P) ^2 + ( B) ^2
(AC) ^2 = ( AB) ^2 + ( BC) ^2
( AC) ^2. = ( 24)^2 + ( 7)^2
( AC) ^2. = 576 + 49
( AC) ^2 = 625
AC = √625
AC = 25 cm
hence AC side 25 cm
=======================
then
To find sin A
Sin. A = 24 / 25
================
COS A = 7 /25
================
in second part
==============
to find Sin C
we use formula
= perpendicular / hypotenuse
============================
Sin C = 24 /25
===============
COS C. = Base / hypotenuse
============================
COS C = 7 /25
===================
hope it helps
thank you
Attachments:
Similar questions