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There are 3 bond pair and 0 lone pair in BF3 , so, hybridisation of BF3 is sp². and in NH3 , there are 3 bond pair and 1 lone pair .so, hybridisation of NH3 is sp³.
after the reaction , hybridisation of B changes to sp³ but hybridisation of N remains the same because N shares its lone pair with electron deficient B .
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Anonymous:
can find the hybridization of an atom by finding its steric number: The steric number = the number of atoms bonded to the atom + the number of lone pairs the atom has. If the steric number is 4, the atom is s p 3 hybridized. If the steric number is 3, the atom is s p 2 hybridized.
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