Question

Plz solve the problem and with trik​

Answer 1

tanA + cotA = 2

=> A = 45°

tan45° = cot45° = 1

Then,

${ \tan }^{12} 45 \: + \: { \cot}^{12} 45 \\ \\ = > {(1)}^{12} + {(1)}^{12} \\ \\ = > 1 + 1 = 2$

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