Question

plz solve the problem find the smallest perfect square number which is divisible by 8 and12​

Answer 1

Answer:

find the lcm of 8 and 12

lcm=24=2³×3

since 2 and 3 do not form a pair we will multiply the lcm by 2×3=6

24×6=144=12²

so 144 is the smallest perfect square number

Step-by-step explanation:

Answer 2

LCM of 8 and 12=2*2*2*3

=24

here 2and 3 are left unpaired

so multiply the LCM by the product of unpaired digits ie 24*2*3=144