Question

plz..solve the qudratic equation by factorisation method​

Answer 1

Answer:

by middle term splitting.

product= -120

sum= -14

-20,6

8x^2-14x-15

=8x^2+6x-20x-15

2x(4x+3)-5(4x+3)

= (2x-5)(4x+3).

roots are-

• 2x-5=0

2x= 5

x= 5/2= 2.5

• 4x+3=0

4x= -3

x= -3/4

therefore roots of the above equation are- 2.5,-3/4.

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Answer 2

ANSWER:

• Value of x is 5/2 and -3/4

GIVEN:

• 8x²-14x-15=0

TO FIND:

• Value of 'x'.

SOLUTION:

=> 8x²-14x-15=0

=> 8x²-20x+6x-15=0

=> (8x²-20x)+(6x-15)=0

=> 4x(2x-5) +3(2x-5)=0

=> (2x-5)(4x+3)=0

Either (2x-5) = 0

=> 2x-5 = 0

=> 2x = 5

=> x = 5/2

Either (4x+3)=0

=> 4x+3 = 0

=> 4x = -3

=> x = (-3)/4

Value of x is 5/2 and -3/4

In this way we can factorise and find the solution of x.

NOTE:

some important formulas:

• (a+b)² = a²+b²+2ab
• (a-b)² = a²+b²-2ab