plz solve the question 17 and 18
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Area of quadrilateral =
Area of ABC+Area of ACD
=AC/2(BD+EF)
=25*6/2=75cm²
Triangle DAB and CBD are right angled
since the follope PYTHAGOROS theorem
Area=BD/2(AD=BC)
=7(128)
=896cm²
PLZ MARK AS BRAINLIEST IF HELPFUL!!!!!!!!
Area of ABC+Area of ACD
=AC/2(BD+EF)
=25*6/2=75cm²
Triangle DAB and CBD are right angled
since the follope PYTHAGOROS theorem
Area=BD/2(AD=BC)
=7(128)
=896cm²
PLZ MARK AS BRAINLIEST IF HELPFUL!!!!!!!!
75 and 896
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