evolute sec16 degree into cosec 74 degree minus cot 74 degree into tan 16 degrees and justify your answer
Answers
Answered by
13
It's answer is 1
It can be solved with the formula sec(90_0)=cosec0
Tan (90_0)=cot
And
1+tan square0 = cosec square0
It can be solved with the formula sec(90_0)=cosec0
Tan (90_0)=cot
And
1+tan square0 = cosec square0
Answered by
24
we know sec(90-theta)=cosec theta
cot (90-theta)=tan theta
now in question
we write sec(90-74)*cosec74-cot74*tan(90-74)
now... cosec74*cosec74-cot74*cot74
cosec^2 74-cot^2 74
we know cosec sq theta-cot sq theta =1
now cosec sq 74-cot sq 74=1
HENCE ANSWER IS 1
HOPE TJIS HELP MARK IT AS BRAINLIEST
cot (90-theta)=tan theta
now in question
we write sec(90-74)*cosec74-cot74*tan(90-74)
now... cosec74*cosec74-cot74*cot74
cosec^2 74-cot^2 74
we know cosec sq theta-cot sq theta =1
now cosec sq 74-cot sq 74=1
HENCE ANSWER IS 1
HOPE TJIS HELP MARK IT AS BRAINLIEST
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