volume of oxygen at ntp required to completely burn 1 kg of coal is
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Coal is carbon(C)
C+O2=CO2
Mass of 1 mole of C is 12g
Vol of 1 mole of O2 is 22.4cm3
1kg C = 1000g/12g=1000/12 moles
1 mole of C needs 2 moles of O2
1000/12 moles of C needs 2000/12 moles of O2
2000/12 moles of O2=(2000*22.4)/12
=3733.33cm3
C+O2=CO2
Mass of 1 mole of C is 12g
Vol of 1 mole of O2 is 22.4cm3
1kg C = 1000g/12g=1000/12 moles
1 mole of C needs 2 moles of O2
1000/12 moles of C needs 2000/12 moles of O2
2000/12 moles of O2=(2000*22.4)/12
=3733.33cm3
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Answer:
Mass of C = 1000 g
1 moles C requires 1 mole O₂ to burn.
Thus, 83.34 mole C requires 83.34 moles O₂
At NTP, 1 mole gas occupies 22.4 litres.
83.34 moles occupies 83.34 × 22.4 = 1.86 × 10³ L
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