Question

Plz solve the question!

Answer 1

Here y = x³㏒x => y' = x³.1/x+3x².㏒x
                             y' = x²+3x².㏒x
  
Again  differentiating both sides we get 
y'' = 2x+6x.㏒x+3x².1/x
=
y'' = 5x+6x.㏒x

Differentiating again....
y''' = 5+6.㏒x+6x/x
=> y"' = 11+6㏒x