plz solve the question
2)
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lakshaymadaan18:
In which class?
Answer(i) (0, 0) (ii) (-1, -2), (-1/10, 7/10) (iii) none
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Answered by
0
3x-y+1=0
-y+1=0
-y=0-1
-y=-1
3x-1+1=0
3x-0=0
3x=0-0
3x=0
x=3/0
x=0
so,x=0
y=(-1)
its is prove
most easiest way
-y+1=0
-y=0-1
-y=-1
3x-1+1=0
3x-0=0
3x=0-0
3x=0
x=3/0
x=0
so,x=0
y=(-1)
its is prove
most easiest way
it's wrong..
where is 3x gone in second step....????
Which question have you done can be solved by either substitution method or elimination method.
because it has two equations and one equation is involved in question itself.
Answered by
1
x² + y² + 5x = 0
(i) x = 0
= (0)² + y² + 5(0)
= 0 + y² + 0
y² = 0
y = +-√0
y = 0
(0,0) Ans.
Rest, (ii) and (iii), you can either do substitution method or elimination method.
(i) x = 0
= (0)² + y² + 5(0)
= 0 + y² + 0
y² = 0
y = +-√0
y = 0
(0,0) Ans.
Rest, (ii) and (iii), you can either do substitution method or elimination method.
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