Question

plz solve the question by formula

(7+3√5)^2
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Answer 1

$\huge \bold{hello}$

We have an identity:

(a+b)²=a²+b+2ab

(7+3√5)²=(7)²+(3√5)²+2(7)(3√5)

➡49+9×5+42√5

➡49+45+42√5

➡94+42√5

Answer 2

HEY BUDDY....HERE'S YOUR ANSWER....

$= (7 + 3 \sqrt{5}) {}^{2}$

The formula:-

(a+b)^2=a^2+2ab+b^2

So,

$= (7) {}^{2} + 2(7)(3 \sqrt{5} ) + (3 \sqrt{5}) {}^{2}$

$= 49 + 42 \sqrt{5} + 45$

$= 94 + 42 \sqrt{5}$

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