Question

plz solve the question in the attachment :- ​​

Answer 1

$\huge\underline {\fbox{solution}}$

$\bold{ \underline{ \underline {\bigstar \: \angle \: es\: of \: the \: \triangle \: are -}}}\\ \circ \: x - 40 \degree \\ \circ \: x - 20 \degree \\ \circ \: \frac{1}{2}x - 10 \degree$

$\sf as \: we \: know - \\ \bold{ \underline{\underline{\leadsto \red{\: sum \: of \: all \: the \: angles \: of \: a \: \triangle \: = 180 \degree}}} }$

$\sf :\mapsto \: x - 40 \degree + x - 20 \degree + \frac{1}{2}x - 10 \degree= 180 \degree$

$\sf: \mapsto \: \frac{5x}{2} - 70 \degree = 180 \degree$

$\sf: \mapsto \: \frac{5x}{2} = 250$

$\sf: \mapsto \: 5x = 500$

$\sf : \mapsto \: x = \frac{500}{5}$

$: \longmapsto \: x = 100$

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