Question

plz solve this.....​

Answer 1

Recall:

• $\cos \theta = \dfrac{\text{Adjacent}}{\text{Hypotenuse} }$

• Sum of all angles in a triangle is 180°

Find angle BAC:

$\cos \theta = \dfrac{\text{Adjacent}}{\text{Hypotenuse} }$

$\cos (\angle BAC) = \dfrac{3}{\sqrt{12} }$

$\angle BAC = \cos^{-1} \bigg( \dfrac{3}{\sqrt{12} } \bigg)$

$\angle BAC = 30^\circ$

Find angle ACB:

Sum of angles in a triangle is 180°

$\angle ACB = 180 - 90 - 30$

$\angle ACB = 60&^\circ$

Answer: 30° and 60°