Math, asked by BloomingBud, 1 year ago

plz solve this 3 equations 5a=50-t1
5a=t1-10
15a=t2-150

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Answers

Answered by Abhishek12111
1
5a+t1=50..(1)
5a-t1=-10...(2)
then t1 =30
a=4
put value of
a in 15a=t2-150
then t2=210
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Answered by Anonymous
6

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5a=50-t1....eq1

5a=t1-10.....eq2

15a=t2-150..eq3

Eq1=eq2

50-t1=t1-10

60=2t1

t1=30

From Eq1..

5a=50-(30)

5a=50-30

5a=20

a=4

From Eq3

15(4)=t2-150

60=t2-150

t2=210

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