Plz solve this.........
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Let the speed of Joseph = xkm/h
Let the speed of Hamid = ykm/h
When approaching one another, combined speed = (x+y)km/h
Time taken to meet = 30/(x+y) = 1/3 (20 minutes = 1/3 hours)
x+y = 90 ------ (i)
When moving in opposite direction, combined speed = (x-y)m/h
Time taken for Hamid to catch up = 30/(x-y) = 3
x-y = 10 ---- (ii)
Solving (i) and (ii) simultaneously
x+y = 90
x-y = 10
_______
2x = 80
x = 40
y = 50
∴ Speed of Joseph = 40km/h
Speed of Hamid = 50km/h
If this is helpful please mark it as brainliest answer ☺
Let the speed of Hamid = ykm/h
When approaching one another, combined speed = (x+y)km/h
Time taken to meet = 30/(x+y) = 1/3 (20 minutes = 1/3 hours)
x+y = 90 ------ (i)
When moving in opposite direction, combined speed = (x-y)m/h
Time taken for Hamid to catch up = 30/(x-y) = 3
x-y = 10 ---- (ii)
Solving (i) and (ii) simultaneously
x+y = 90
x-y = 10
_______
2x = 80
x = 40
y = 50
∴ Speed of Joseph = 40km/h
Speed of Hamid = 50km/h
If this is helpful please mark it as brainliest answer ☺
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