Question

plz solve this...............................????????????​

Answer 1

Step-by-step explanation: Let the thita be A. Then

we know that sin2A-sin2B = sin (A+B)sin(A-B)

π/8 + a/2+π/8 - a/2) sin(π/8 + a/2-π/8+ a/2)sin^2[π÷8+A÷2]-sin^2[π÷8-A÷2]=sin(

π/4) sin(a)=sin(

=(1/\sqrt{2} ) sina