plz solve this and dont post irrelevant answers
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Answer:
Value of a³+b³-3ab = -1
Step-by-step explanation:
Given a+b=-1 ----(1)
On cubeing both sides of equation (1), we get
(a+b)³ = (-1)³
we know the algebraic identity:
=> a³+b³+3ab(a+b)= -1
=> a³+b³+3ab(-1)=-1
/* from (1)*/
=> a³+b³-3ab = -1
Therefore,
Value of a³+b³-3ab = -1
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