Question

plz solve this. By giving proper steps and explanation​

Answer 1

Answer:-

a=2 and b =-1

Step-by-step explanation:-

$\frac{\sqrt{3}-1 }{\sqrt{3} +1}$ = a + b√3

⇒$\frac{\sqrt{3}-1 }{\sqrt{3} +1}$ × $\frac{\sqrt{3} -1}{\sqrt{3}-1 }$ = a + b√3

⇒$\frac{(\sqrt{3}-1)^2 }{(\sqrt{3} )^2 - (1)^2}$ = a + b√3

⇒ $\frac{3 +1-2\sqrt{3} }{3-1}$ = a + b√3

⇒$\frac{4-2\sqrt{3} }{2}$ = a + b√3

⇒$\frac{2(2-\sqrt{3}) }{2}$ = a + b√3

⇒2 - √3 = a + b√3

Answer⇒ a=2 and b =-1

I hope that this helped you :-)