Math, asked by riya590, 1 year ago

plz solve this by giving whole solution

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Answered by Anonymous
0
hi here is ur awswer
ans=2
hope it helps



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Answered by Anonymous
2
Hey Mate !

Here is your solution :

Given,

p( x ) = x² - ( 2k - 2 )x + ( 2k + 1 )

Product of zeroes = ( 3/2 ) Sum of zeroes

Here,

Coefficient of x² ( a ) = 1

Coefficient of x ( b ) = -( 2k -2 )

Constant term ( c ) = ( 2k + 1 )

Let , α and β be its zeroes.

We know the relationship between zeroes and coefficients of x.

=> Sum of zeroes = -b/a

=> α + β = -[ - ( 2k - 2 ) ] / 1

=> α + β = ( 2k - 2 )

And,

=> Product of zeroes = c/a

=> αβ = ( 2k + 1 ) / 1

=> αβ = ( 2k + 1 )

Now,

=> Product of zeroes = ( 3/2 ) Sum of zeroes


=> αβ = ( 3/2 ) ( α + β )

By substituting the value of ( α + β ) and αβ.

=> ( 2k + 1 ) = ( 3/2 ) ( 2k - 2 )

=> ( 2k + 1 ) = ( 3/2 ) 2 ( k - 1 )

=> ( 2k + 1 ) = 3 ( k - 1 )

=> 2k + 1 = 3k - 3

=> 1 + 3 = 3k - 2k

=> 4 = k

Hence , the answer is option ( d ) 4.

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Hope it helps !! ^_^





Anonymous: :-)
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