plz solve this by long division
Attachments:
Answers
Answered by
1
x^3-2x^2-x+2
put x=1
1^3-2×1^2-1+2
=0
1 is zero is p(x).
hence x-1 is factor of p(x).
by long division,we get,
p(x)=(x-1)(x^2-x-2)
=(x-1)(x-2)(x+1)
put x=1
1^3-2×1^2-1+2
=0
1 is zero is p(x).
hence x-1 is factor of p(x).
by long division,we get,
p(x)=(x-1)(x^2-x-2)
=(x-1)(x-2)(x+1)
Answered by
0
Khud Karrrrrrrrrrrrrrrrrrrrrrrrrrr
Similar questions