plz solve this equation i have tried 3 times but i haven't got the answer!!
solve the following pair of linear equation by the substitution method.
0.2x + 0.3y = 1.3
0.4x + 0.5y = 2.3
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The solution is as follows:-
0.2x=1.3-0.3y
Putting this in the second equation we have
2*(1.3-0.3y)+0.5y=2.3
2.6-0.6y +0.5y=2.3
-0.1y=-0.3
y=3
Putting the value of y in the equation 1
0.2x=1.3-0.3*3
0.2x=0.4
x=2
Thus y=3 and x=2 which satiesfies the given equations.
0.2x=1.3-0.3y
Putting this in the second equation we have
2*(1.3-0.3y)+0.5y=2.3
2.6-0.6y +0.5y=2.3
-0.1y=-0.3
y=3
Putting the value of y in the equation 1
0.2x=1.3-0.3*3
0.2x=0.4
x=2
Thus y=3 and x=2 which satiesfies the given equations.
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