Question

plz solve this fast​

Answer 1

Given :-

• Principal (P) = Rs.4000
• Rate (R) = 10%
• Time (t) = 1 1/2 ↪3/2 ↪ 1.5 years.

To Find :-

• Compound interest (CI) = ?

Solution :-

As we know that,

$\tt \: \red{A = P(R + \frac{1}{100})^t}$

[ Putting values ]

↪A = 4000 (10 + 1/100)^1.5

↪ A = 4000 (10 + 100/100)^1.5

↪ A = 4000(110/100)^1.5

↪ A = 4000(11/10)^1.5

↪ A = 4000 × 1.1536

↪ A = 4614.4

↪ .°. Amount = Rs. 4614.4

We know that,

↪ Interest = Amount - Principal

↪ I = 4614.4 - 4000

↪ I = 614.4

↪ .°. CI = Rs. 614.4.

Hence,

• Required Compound interest is Rs.614.4.