Question

Plz.. solve this ...fast..

Answer 1

since the volume of sphere having radius R1 = r
is given by (4/3)πr^3
if the radius is reduced by 1/3 then R2= r/3 ...
since new volume will be ...
$\frac{4}{3} \pi {( \frac{r}{3}) }^{3} \\ \frac{4}{3} \pi {r}^{3} \times ( \frac{1}{27} ) \\ the \: volume \: is \: \frac{1}{27} f \: its \: previous \: volume$