Math, asked by darshuuuuu, 10 months ago

plz solve this...fast urgent​

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Answered by DarkBeats
9

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\Large{x=2+\sqrt{3}}

To Find--

\Large{x+\frac{1}{x}}

Value of -- \large{\frac{1}{x}}

➡️\frac{1}{x}=\frac{1}{2+\sqrt{3}}

➡️\frac{1}{2+\sqrt{3}}×\frac{2-\sqrt{3}}{2-\sqrt{3}}

➡️\frac{1×(2-\sqrt{3})}{2^2-\sqrt{3}^2}

➡️\frac{2-\sqrt{3}}{4-3}

➡️\frac{1}{x}=2-\sqrt{3}

Using this in \large{x+\frac{1}{x}}

➡️2+\sqrt{3}+2-\sqrt{3}

➡️⭐\huge{\orange{Answer=4}}

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Formula Used--

♥️\Large{(a-b)(a+b)=a^2-b^2}♥️

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Answered by avman08
0

Answer:

hi here is your answer mate

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