Math, asked by parth218, 1 year ago

plz solve this friends

Attachments:

Answers

Answered by lumbi
5
i hope it helps u..if not plzz dont report me
Attachments:

lumbi: can u plzz mark me brainliest
Swarup1998: Your answer is correct. Don't type "Don't report" from next answers.
Answered by Swarup1998
0
The answer is given below :

 {(2 - \sqrt{3}) }^{ - 3} + {(2 + \sqrt{3}) }^{ - 3} \\ \\ = \frac{1}{ {(2 - \sqrt{3}) }^{3} } + \frac{1}{ {(2 + \sqrt{3} )}^{3} } \\ \\ = \frac{ {(2 + \sqrt{3}) }^{3} + {(2 - \sqrt{3}) }^{3} }{ ({(2 - \sqrt{3} )(2 + \sqrt{3} ) })^{3} } \\ \\ = \frac{ {2}^{3} + 3( {2}^{2})( \sqrt{3} ) + 3(2) {( \sqrt{3} )}^{2} + {( \sqrt{3} )}^{3} + {2}^{3} - 3( {2}^{2})( \sqrt{3} ) + 3(2) {( \sqrt{3} )}^{2} - {( \sqrt{3} )}^{3}}{ {(4 - 3)}^{3} } \\ \\ = \frac{(2 \times {2}^{ 3} ) + (2 \times 6 \times 3) }{ {1}^{3} } \\ \\ = \frac{16 + 36}{1} \\ \\ = 52

Thank you for your question.
Similar questions