plz solve this .... help me guys plz ....
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your question is
(2 cos ² 60⁰+4cos²45⁰+tan²60⁰+3cosec²60⁰+1)/(3sec60⁰-7/2sec²45+2cosec30⁰-1)
= [ 2×1/4+4×1/2+3+4/3+1]/(3×2-7+4-1)
= (1/2+2+3+4/3+1)/(6-7+4-1)
= (47/6)/2
= 47/12
=3.91
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