Question

plz solve this..ill mark u as brainliest....plzz fast fast guys..common..​

Answer 1

$cot^2A-cot^2B= \frac{Cos^2A}{Sin^2A} -\frac{Cos^2B}{Sin^2B} \\ = \frac{Cos^2A.Sin^2B-cos^2BSin^2A}{Sin^2ASin^2B} \\\\ =\frac{Cos^2A.(1-Cos^2B)-cos^2B(1-Cos^2A)}{Sin^2ASin^2B}\\\\\ =\frac{Cos^2A-Cos^2BCos^2A-cos^2B+Cos^2Acos^2B}{Sin^2ASin^2B}\\ = \frac{Cos^2A-cos^2B}{Sin^2ASin^2B}\\LHS=RHS so proved Mark as brainiest if it helped$

Mark as brainliest if it helped( mistakenly added the line in the math pop up box XD)