plz solve this math question,,,,,, @laughterqueen sista,,,,
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Heya mate, Here is ur answer
Given : C's age 3 years back = 3 years
So, C's present age =3+3=6 years.
B is Five times older than C
So, B's present age =5×6
=30 years.
After five years,
B's age =30+5
=35 years
A/Q
A's age after 5 years =3×B's age after 5 years
=3×35
=105 years.
So,A's age after 5 years =105 years.
So, A's present age =105-5
=100 years.
Warm regards
@Laughterqueen
◦•●◉✿[Tʜᴀɴᴋ ʏᴏᴜ]✿◉●•◦
Be Brainly ✌✌✌
Given : C's age 3 years back = 3 years
So, C's present age =3+3=6 years.
B is Five times older than C
So, B's present age =5×6
=30 years.
After five years,
B's age =30+5
=35 years
A/Q
A's age after 5 years =3×B's age after 5 years
=3×35
=105 years.
So,A's age after 5 years =105 years.
So, A's present age =105-5
=100 years.
Warm regards
@Laughterqueen
◦•●◉✿[Tʜᴀɴᴋ ʏᴏᴜ]✿◉●•◦
Be Brainly ✌✌✌
SillySam:
☺☺ Thanks for the question...btw a nice question
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