Question

plz solve this one....​

Answer 1

angle 1 = angle 3

a b upon GF equals to CG upon CA

10TH TRIANGLE ABC SIMILAR TO TRIANGLE CGA

Answer 2

In ∆ADE and ∆GCF
/_ DAE = /_ FGC ...(corresponding angles are equal because GF || AB
Now,
/_ AED = /_ GFC ...(each 90°)

Hence, by Angle - Angle similarity
Proved that
∆ADE ~ ∆ GCF

Hope this helps you !