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Answers
Answer:
Q1: (D)
Q2: (B)
Q3: (B)
Q4: (D)
Q5: (C)
Q6 (B)
Q7 (B)
Q8 (B)
Q9 (B)
Q10 (A)
Step-by-step explanation:
Q1:
d= -4 n=7 an=4
an=a+(n-1)d
4=a+(7-1)(-4)
4=a-24
Therefore, a=28 option (D)
Q2:
a=3.5 d=0 n=101
an=a+(n-1)d
an=3.5+(101-1)0
Therefore, an=3.5 option(B)
Q3:
A.P:-10,-6,-2,2
d=a2-a1
-6-(-10)=4
Therefore, option(B) an AP with d=4
Q4:
a11=-5+10*(5/2)
a11=5+25
a11=30
Therefore, option(D)30
Q5:
option(C)
Q6:
a=-3 d=7
a21=a+(n-1)d
a21=-3+20*7
a21= -3+140
a21=137
Therefore, (B)137
Q7:
a2=13 a5=25
a+d=13 (1) a+4d=25 (2)
(2)-(1)
3d=12
∴d=4
∴a=9
a7=a+6d
a7=9+6*4
a7=9+24
a7=33
Therefore, 7th term is 33 option(B)
Q8:
an=210
a+(n-1)d=210
21+(n-1)21=210 (divide by 21)
1+(n-1)=10
(n-1)=9
n=10
There, option(B) 10th term
Q9:
a18-a13
a+17d-[a+12d]
5d
5*5
25
Therefore option(C)
Q10:
a18-a14=32
a+17d-[a+13]=32
4d=32
d=8
Therefore option(A)8