Question

plz solve this problem
A refrigerator was bought for rs. 23,440 and rs.1000 were spent on its installation. it was sold for rs.22,560. find the loss percentage.​

Answer 1

Answer:

7.69 percent

Step-by-step explanation:

cp of fridge = 23440

extra amount = 1000

so , new cp = 24440

sp = 22560

loss = cp - sp

= 1880

loss percent = loss/ cp * 100

= 1880/24440*100

= 7.69

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Answer 2

Answer:

Required loss percentage is 7.69%

Step-by-step explanation:

Given,a refrigerator was bought for rs. 23,440.

Therefore cost price of the refrigerator is 23440 rupees.

and it is also given that he spent 1000 rupees for installation.

So,total cost price

$= (23440 + 1000) \\ = 24440 \: rupees$

Again given it was sold for rs.22,560.

So, selling price of the refrigerator $= 22560 \: rupees$

We know,cost price means 100%.

So, 24440 rupees means 100%

By Unitary method, 1 rupees means $\frac{100}{24440} \%$

So,22560 means

$\frac{100}{24440} \times 22560 \\ = 92.31\%$

So, required loss percentage

$= (100 - 92.31)\% \\ = 7.69\%$

This is a problem of percentage.

Know more about percentage,

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