plz solve this question
Answers
Given,
Molarity of HCl = 0.76M
Volume of HCl = 250 ml
Mass of CaCO₃ reacting = 1000 grams
Now, let us first calculate the number of moles of each reactant.
Number of moles of HCl = Molarity x Volume (in litres)
= 0.76 x 0.25
= 0.19 moles
Number of moles of CaCO₃ = given weight / Molecular weight
= 1000/100
=10 moles
The Balanced chemical equation is
CaCO₃ + 2 HCl ----> CaCl₂ + CO₂ + H₂O
From above, 2 moles of HCl reacts with 1 mole of CaCO₃ and gives 1 mole of CaCl₂
So, 0.19 moles of HCl will react with "0.19/2" moles of CaCO₃ and gives "0.19/2" moles of CaCl₂
Hence, Moles of CaCl₂ formed = 0.19/2 = 0.095 moles
Limiting reagent: The reactant that gets completely consumed after the reaction completes is known as limiting reagent
Excess reagent: The reactant that is still present unreacted even after the reaction completes is known as excess reagent
Here, as HCl is completely consumed, it is the Limiting reagent, while CaCO₃ is the excess reagent.