find the dimenaion of c in the x= a+ bt/ c-t^3
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Dimension of a,bt,ct2 should be equal to x
x=[L]
So, the dimension of bt will be equal to that of 'x'.
bt=[L]
b=[T][L]
b=[LT−1]
The dimension of c can be obtained as:
ct2=[L]
c=[T2][L]
c=[LT−2]
Hope it helps.
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