Math, asked by Flparid5e, 10 months ago

The magnitude, M, of an earthquake is defined to be M = log StartFraction I Over S EndFraction, where I is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and S is the intensity of a “standard” earthquake, which is barely detectable. What is the magnitude of an earthquake that is 35 times more intense than a standard earthquake? Use a calculator. Round your answer to the nearest tenth.

Answers

Answered by amitnrw
78

Given :  The magnitude, M, of an earthquake is defined to be M = log (  I/S) . earthquake   is 35 times more intense than a standard earthquake

To find :   magnitude of an earthquake

Solution:

The magnitude, M, of an earthquake  =  log(  I/S)

I   = Intensity of earth Quake

S  = intensity of standard Earth Quake

earthquake is 35 times more intense than a standard earthquake

=> I  = 35S

=> The magnitude, M, of an earthquake  =  log(  35S/S)

= log 35

= 1.544

Magnitude of Earth Quake = 1.5  

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Answered by merpweepwomp
66

Answer:

the answer is 1.5

Step-by-step explanation:

i just did this problem and assumed that since we didn't get the number for S, we would only have to find the log of 35. after plugging log35 into a calculator, the answer rounds to 1.5! hope this helps

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