Question

plz solve this question​

Answer 1

I think you will like me answer please marked as brainliest

Answer 2

Answer:

a=14,b=0

Step-by-step explanation:

on cross multiplying we get $\frac{ {(2 + \sqrt{3} )}^{2} + {(2 - \sqrt{3} )}^{2} }{(2 + \sqrt{3} )(2 - \sqrt{3} )} = a +b \sqrt{3}$

we know that (a+√b)(a-√b)=a²-b

$\frac{4 + 3 + 4 \sqrt{3} + 4 + 3 - 4 \sqrt{3} }{ {2}^{2} - { \sqrt{3} }^{2} } = a+ b \sqrt{3}$

on simplifying we get

$\frac{4 + 3 + 4 \sqrt{3} + 4 + 3 - 4 \sqrt{3} }{ 4 - 3} = a + b \sqrt{3}$

$\frac{14 + 0 \sqrt{3} }{1} = a + b \sqrt{3}$

$14 + 0 \sqrt{3} = a + b\sqrt{3}$

on comparing we get a=14 and b=0

Please mark it as brainliest

Thanks