Question

plz solve this question

Answer 1

HELLO DEAR,




we know that

∠ADO' = 90°
( O'D is perpendicular to AC)

∠ACO= 90°

 {OC(radius)perpendicular to AC(tangent)}

In ∆s ADO'and ACO ,

∠ADO' = ∠ACO ( each 90°)

∠DAO = ∠CAO (common)

by AA criterion ,triangles ADO' and ACO are

similar to each other.

AO'/AO = DO'/CO

( corresponding sides of similar triangles )

AO = AO' + O'X + OX

= >3AO'

( AO'=O'X=OX radii of the two circles are equal )

AO'/AO = AO'/3AO =1/3

DO'/CO=AO'/AO = 1/3

DO'/CO =1/3.

I HOPE ITS HELP YOU DEAR,
THANKS