Question

plz solve this question.

Answer 1

HELLO DEAR,

let theta=alpha

NOW

given that:-

SIDE OF EQIALATERAL TRIANGLE IS 8 CM

.it is equilalateral triangle

then the angle is 60°

it means alpha =60°

AREA FOR SHADED REGION

=> area of equilalateral triangle -
3×(area of sector of theta is 60° and radius is 4cm)

now put This value in the formula

we get,

$\frac{ \sqrt{3} }{4} {a}^{2} - 3( \frac{ \alpha }{360} \times \pi {r}^{2} ) \\ = > \frac{ \sqrt{3} }{4} \times {8}^{2} - 3( \frac{60}{360} \times \frac{22}{7} \times {4 }^{2} ) \\ = > \sqrt{3 } \times 16 - 3( \frac{1}{6} \times \frac{22}{7} \times 16) \\ = > 16 \sqrt{3} - \frac{3 \times 8 \times 2 \times 22}{3 \times 2 \times 7} \\ = > 16 \sqrt{3} - 3.14 \times 8 \\ = > 16 \times 1.732 - 3.14 \times 8 \\ = > 27. 712- 25.12 \\ = >2.472 c {m}^{2}$

I HOPE ITS HELP YOU DEAR,
THANKS