Math, asked by birendra3, 1 year ago

plz solve this question

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Answered by akshatrock111
1
I think that it will help you
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Answered by BloomingBud
0
Given :-
diagonal 1 (d1) = 12 cm = AC
diagonal 2 (d2) = 16 cm = BD

(as one of the property of rhombus = the two diagonals bisect each other at right angle)

So,
AO = OC = 6cm each
DO = OB = 8cm each

AOB, BOC, COD, DOA all are right angled triangle

Triangle AOB
 {(AB) }^{2}  +  {(OB )}^{2}  =  {( AB})^{2}  \\  \\  {6}^{2}  +  {8}^{2}  =  {( AB)}^{2}  \\  \\ 36 + 64 = {( AB)}^{2} \\  \\  100 = {( AB)}^{2} \\  \\  \sqrt{100}  = AB \\  \\ 10 = AB

AB = 10cm

As another property of rhombus = all sides are equal
AB = BC = CD = DA

each side of rhombus = 10cm
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