Question

plz solve this question

Answer 1

I think that it will help you

Answer 2

Given :-
diagonal 1 (d1) = 12 cm = AC
diagonal 2 (d2) = 16 cm = BD

(as one of the property of rhombus = the two diagonals bisect each other at right angle)

So,
AO = OC = 6cm each
DO = OB = 8cm each

AOB, BOC, COD, DOA all are right angled triangle

Triangle AOB
${(AB) }^{2} + {(OB )}^{2} = {( AB})^{2} \\ \\ {6}^{2} + {8}^{2} = {( AB)}^{2} \\ \\ 36 + 64 = {( AB)}^{2} \\ \\ 100 = {( AB)}^{2} \\ \\ \sqrt{100} = AB \\ \\ 10 = AB$

AB = 10cm

As another property of rhombus = all sides are equal
AB = BC = CD = DA

each side of rhombus = 10cm