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Given :-
diagonal 1 (d1) = 12 cm = AC
diagonal 2 (d2) = 16 cm = BD
(as one of the property of rhombus = the two diagonals bisect each other at right angle)
So,
AO = OC = 6cm each
DO = OB = 8cm each
AOB, BOC, COD, DOA all are right angled triangle
Triangle AOB

AB = 10cm
As another property of rhombus = all sides are equal
AB = BC = CD = DA
each side of rhombus = 10cm
diagonal 1 (d1) = 12 cm = AC
diagonal 2 (d2) = 16 cm = BD
(as one of the property of rhombus = the two diagonals bisect each other at right angle)
So,
AO = OC = 6cm each
DO = OB = 8cm each
AOB, BOC, COD, DOA all are right angled triangle
Triangle AOB
AB = 10cm
As another property of rhombus = all sides are equal
AB = BC = CD = DA
each side of rhombus = 10cm
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