Question

plz solve this question
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Answer 1

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Answer 2

$\LARGE{\underline{\green{\sf{Answer:}}}}$

$(a+b)² + ( a-b)² = 2(a² + b² )$

$\LARGE{\underline{\green{\sf{Solution\: with\: explanation: }}}}$

[ A^B means “ A ” to the power of “ B ” ]

Given , (a+b)² + (a-b)² = ?

We know that ,

(a+b)² = a² + b² + 2ab ———equation 1

We also know that ,

(a-b)² = a² + b² - 2ab ———equation 2

.

So, in order to find sum of (a+b)² and (a-b)² ,

i.e (a+b)² + ( a-b) ²,

we need to add equations 1 and 2 .

.

So , by adding equations 1 and 2 , we get ,

=> (a+b)² + (a-b)² = a² + b² + a² + b²

= 2(a² + b² )

As, ( + 2ab ) and (—2ab ) terms get cancelled.

.

Therefore ,

(a+b)² + ( a-b)² = 2(a² + b² ) .

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$explanation\:\:completed\:!$