Question

plz solve this question

Answer 1

for first question
$( {3x})^{3} + ( {2x})^{3} = (3x + 2y) \\ (9 {x}^{2} + 4 {y}^{2} - 6xy)$
put the value from given data
$= 14(( {3x + 4y})^{2} - 24xy - 6xy) \\ = 14( {14}^{2} - 30 \times 8)$
$= 14(196 - 240) \\ = 14 \times - 44 \\ = - 616$
for second put values 20 and 14/9 instead of 14 and 8
$= 20( {20}^{2} - 30 \times \frac{14}{9} ) \\ = 20(400 - \frac{140}{3} )$

$= 20( \frac{1200 - 140}{3} ) \\ = 20( \frac{1060}{3} )$
$= \frac{21200}{3}$

hope it may help you