Math, asked by Henry141, 11 months ago

plz solve this question

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Answered by monidhana
1
tanA=√sec^2A-1,sins=√sec^2-1/secA,cosa=1/secA,cosecA=secA/√sec^2A-1 and cotA=1/√sec^2A-1.

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Answered by SuadMalik
1
hey plz mark as brain list


Some identities are:

1) cos² A + sin²A = 1


2) sec² A - tan² A = 1.


3) cosec² A - cot² A = 1.

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We know that,

sec A = 1/cos A

⇒ cos A = 1/sec A


cos²A + sin²A = 1

⇒  sin²A = 1 – cos²A

⇒  sin²A = 1 – (1/sec²A)                          (cosA= 1/secA)

⇒  sin²A = (sec²A-1)/sec²A


⇒sinA = √((sec²A-1)/sec²A)


⇒sinA = √(sec²A-1) ÷ (secA)............................(i)



sin A = 1/cosec A

⇒ cosec A = 1/sin A


⇒cosecA= secA ÷√sec²A-1                 (from eq i)


Now,

sec²A – tan²A = 1

⇒ tan²A = sec²A + 1


⇒tanA = √sec²A + 1.....................................(ii)


tan A = 1/cot A

⇒ cot A = 1/tan A


⇒cotA  = 1/√sec²A + 1                  (from eq ii)






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