Question

plz solve this question........

Answer 1

Cut off  part =2   3/5                             = 3    3/10

                    =13 /3                                 =33/10

13/3  +  33/10   of 11m

LCM=30

130/30     +     99/30       of 11m

229/30  of 11m

=2519/30  =30      83/20

=The length of the remaining rope is 30   83/20 m.

Answer 2

total length of the two pieces of ropes=
$13 \div 5 + 33 \div 10 \\ (26 + 33) \div 10 \\ 59 \div 10$
now length of remaining rope =
$11 - 59 \div 10 \\ (110 - 59 ) \div 10 \\ 169 \div 10 \\ 16 \ \frac{9}{10}$