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Hi there!
Here's the answer:
Given,
Relative displacement = 100m
Relative velocity = 0 - (-25)= 25 m/s
time= displacement/velocity
t= 100/25
t= 4
•°• After 4 sec, both stones will meet.
We have
S=ut+(1/2)at²
Here u=0 as stone is falling freely from top of the tower
& a= g= 10 m/s
S= (1/2)gt²
S= (1/2)×10×(16)
S= 80 mts from top of tower
•°• They will meet at 80 mts from top of tower after 4 sec
Here's the answer:
Given,
Relative displacement = 100m
Relative velocity = 0 - (-25)= 25 m/s
time= displacement/velocity
t= 100/25
t= 4
•°• After 4 sec, both stones will meet.
We have
S=ut+(1/2)at²
Here u=0 as stone is falling freely from top of the tower
& a= g= 10 m/s
S= (1/2)gt²
S= (1/2)×10×(16)
S= 80 mts from top of tower
•°• They will meet at 80 mts from top of tower after 4 sec
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