Question

plz solve this question

Answer 1

four consecutive terms of an ap is a , a+d , a+2d and a+3d .

now, sum of four terms is 88

=> a + a+d + a+2d + a+3d = 88

=> 4a + 6d = 88 --------------1


now , sum of first term and third term is 40 .

=> a + a+2d = 40

=> 2a + 2d = 40

=> a + d = 20

=> a = 20 - d --------------2




put the value of a into first equation ,

=> 4(20 - d ) +6d = 88

=> 80 - 4d +6d = 88

=> 2d = 8

=> d = 4

now => a = 20-4= 16

then , a = 16
a+d = 20
a+2d = 24
a+3d = 28

then 4 consecutive integer of an AP is 16 , 20 , 24 and 28 .