Question

plz solve this question asap

Answer 1

Exponents

$\frac{ {9}^{n} \times {3}^{2} \times {3}^{n} - {27}^{n} }{ { ({3}^{m} \times 2) }^{3} } = {3}^{ - 3}$

=> {3^(3n+2) - 3^(3n)}/{3^(3m) × 8} = 3^(-3)

=> [3^(3n){9-1}]/{3^(3m)×8} = 3^(-3)

=> 3^(3n)/3^(3m) = 3^(-3)

=> 3^(3n-3m) = 3^(-3)

=> 3n - 3m = -3

=> n - m = -1

=> m - n = 1 [ proved]

That's it
Hope it helped
^_^