Question

plz solve this question briefly​

Answer 1

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From the given reaction :-

C2H2 + 2H2 ======> C2H6

Rate of disappearance of H2 = 2 × rate of appearance of C2H6

So, ROD (H2) = 2 × 0.4 = 0.8 mol/dm^3

Hence, ROD of H2 is 0.8 mol/dm^3

Answer 2

From the given reaction :-

C2H2 + 2H2 ======> C2H6

Rate of disappearance of H2 = 2 × rate of appearance of C2H6

So, ROD (H2) = 2 × 0.4 = 0.8 mol/dm^3

Hence, ROD of H2 is 0.8 mol/dm^3