Question

Plz solve this question by substitution method....​

Answer 1

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$x - y = 3 \\ \\ or \\ \\ x = 3 + y - - - - - \: equation \: 1 \\ \\ \frac{x}{3} + \frac{y}{2} = 6 \ \\ \\ or \: \\ \\ 2x + 3y = 36 \: - - - - \: equation \: 2 \\ \\ put \: x \: = 3 + y \: in \: equation \: = > 2 \\ \\ = > 2(3 + y) + 3y = 36 \\ = > 6 + 2y + 3y = 36 \\ = > 6 + 5y = 36 \\ = > 5y = 30 \\ \\ \\ = > y = 6 \\ \\ put \: the \: value \: of \: y \: = 6 \: in \: equation \: 1 \\ = > x = 3 + 6 \\ \\ \\ = > x = 9$

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Answer 2

$hi \: ..$

$x - y = 3 \: \:$

$x = 3 + y \: \: \: \: \: ..................(1)$

$\frac{x}{3} + \frac{y}{2} = 6$

$\frac{2x + 3y}{6} = 6$

$2x + 3y = 36 \: \: \: \: \: ...............(2)$

From eq (1) & (2)

$2(y + 3) + 3y = 36$

$2y + 6 + 3y = 36$

$2y + 3y = 36 - 6$

$5y = 30$

$y = \frac{30}{5}$

$y = 6$

NOW, from (1)

x = y + 3

x = 6 + 3

x = 9

THUS ,

solution :

x = 9 ; y = 6

$hope \: \: this \: \: helps \: you \: ..$